Mathematics, 15.10.2019 20:40 wesfleridor

10 ! full answer with full step by step solution

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Answer from: jay13212

A
The velocity is found by differentiating the given cubic.
x'(t) = 2t^3 - 15t^2 + 24t This is the distance
x'(t) = 6t^2 - 20t + 24 This is the velocity (first derivative)
x"(t) = 12t - 20 This is the acceleration (second derivative)
x'(2) = 6(2)^2 - 20*2 + 24
x'(2) = 24 - 40 + 24
x'(2) = 48 - 40
x'(2) = 8 units per second.

x"(2) = 12(2) - 20
x"(2) = 24 - 20
x"(2) = 4 units per second^2

B
at t = 2 the acceleration is positive. That's a pretty good indication that the velocity is increasing.

C
When x(t) is minus, then the particle is moving left.
At t = 0 the object is not moving (x(t) = 0)
Any value less than 0 and the object is moving left. Try a couple of values.
x(-1) = 2(-1)^3 - 15(-1)^2 +24(-1) Whatever that is is minus.
t < 0 will make the object move left.

Answer from: jadabugs8187

A) The velocity and acceleration are the first and second derivatives of x(t), respectively.
x'(t) = 6t² -30t +24
x''(t) = 12t -30

At t=2, the velocity is x'(2) = -12 . . . . units/time unit
At t=2, the acceleration is x''(2) = -6 . . . . units/time unit²

b) Acceleration has the same sign as velocity at t=2, so P is speeding up. When acceleration is in the same direction as velocity, the magnitude of velocity (speed) increases.

c) P is moving left where its velocity is negative, when t is in the interval (1, 4).
10 ! full answer with full step by step solution

10 ! full answer with full step by step solution

Answer from: Quest

see below

step-by-step explanation:

7. there are 10 data points in the set. the middle point is between 5 and 6. the middle point in the top half is 8 and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term point 8 = 100 point 3 = 88

iqr = 100-88 = 12

final point 8 = 93 point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6. b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical . there is an outlier for the males that skews the data

5. the iqr is a better measure of spread for the movies and basketball games. since the basketball game has an outlier, we do not want to use standard deviation for measurement.

3. the exam median is much higher than the class median. the median line is farther to the right on the exams

2. there is no way to tell what the means are from the box and whisker plots.

Answer from: Quest

theres no picture: /

step-by-step explanation:

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