I’m confused as how to solve this problem ?

Let's use W for width and L for length. The perimeter of the court can be expressed as 2W + 2L, so:

2W + 2L = 128

We can simplify this equation by dividing each term by 2 to get:

W + L = 64

We can also solve for one of the variables. Let's subtract L from both sides to solve for W:

W = 64 - L

We also know that:

6L + 9W = 444

Now we can use substitution to solve the system of equations. Plug 64 - L in for W in the second equation:

6L + 9(64 - L) = 444

Distribute the 9:

6L + 576 - 9L = 444

Combine like terms:

-3L + 576 = 444

Solve for L. First we can subtract 576 from both sides:

-3L = -132

Next, divide by -3:

L = 44 ft

Now that we know the length, we can plug it into the perimeter equation to find the width.

88 + 2W = 128

2W = 40

W = 20 ft

The answer is 20 ft wide by 44 ft long.

The answer is budget i believe. hope this but it’s self explanatory.