F(x) = (x - 3)2 on which interval(s) is this function increasing?

X2 -3x

2x2 -6x

X=3

Then solve for f

F(3)=(3-3)2

F=(3x3)-(3x3)2

So f=(9)-(9)2

F=0x2 which is

F=0

0(3)=(3x3)2 then solve

0=(9)2

0=18

So neither is your answer