Mathematics, 26.09.2019 02:00 tobydeathstirke

In blueprints an architects firm drew everything 1/24 of the actual size the windows will actually measure 4feet by 6 feet and the doors measure 12 feet by 8 feet what are the dimensions of the windows and doors

Answers: 1

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Answers

To apply a scale to a measure, you have to follow this rule:

Real measure x Scale = Scaled measure

So the drawings will have:

4 x 1/24 = 0'167 feet
6 x 1/24 = 0'25 feet
Windows: 0'167 by 0'25 feet

12 x 1/24 = 0'50 feet
8 x 1/24 = 0'33 feet
Doors: 0'33 by 0'50 feet

Answer from: juniorgutierrez997

Window size in the image

length = 1/6 feet

width = 1/4 feet

Door size in the picture

length = 1/2 feet

width = 1/3 feet

Further explanation

Scale images are images that represent the real situation. The picture made is given a certain comparison so that it describes the real situation

This particular comparison is called scale

Examples of this scale drawing include maps and floor plans

On a map usually a scale is included

So the scale is a comparison between the distance on the map with the actual distance

an architects uses a scale of 1:24 in the picture

actual size of the windows = 4 x 6 feet

actual size of the doors: 12 x 8 feet

then:

1. The window size in the image is:

length = scale x actual size

length = 1/24 x 4

length = 1/6

width = 1/24 x 6

width = 1/4

2. The size of the door in the picture is:

length = scale x actual size

length = 1/24 x 12

length = 1/2

width = 1/24 x 8

width = 1/3

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a scale on a map

link

keywords: scale, maps, blueprint, doors, windows

In blueprints an architects firm drew everything 1/24 of the actual size the windows will actually m

Answer from: Quest

the answer will be the last one

Which equation represents a line that passes through (4,3/4) and has a slope of 3/4

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

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step-by-step explanation:

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