Use a while loop to determine how many terms in the series 3k^2 are required for the sum to surpass 2000

Using JAVA:
int sum = 0;       
int k = 1;       
while(sum  <= 2000) {           
sum += 3*k*k;           
 k++;       
 }               
System.out.println(k);

Output: 14

Which means it will take 14 terms for the series to surpass 2000

I am assuming k starts at 0. Python code (or pseudocode) would be this:

S = 0
count_term = 0
k = 0
while S <= 2000:    S = S + 3*k**2
    count_term = count_term + 1    k = k + 1

print(count_term)


It will print 14

If k should start at other number then just replace number at third line and execute it.

Answer: 900°

good luck on your studies! : )

david edward.