In cribbage 6 cards are initially dealt from a standard deck. one of the ways to get points is to have a "15", i. e. having a set of 4 or fewer cards whose sum is 15 (j, q,ks all count as 10, a counts as 1, and 2-10 count as their number.) what is the probability of getting exactly 1 "15"? (note 5,10,10,3,3,8 counts as 2 "15"s since the 5 and the first 10 and the 5 and the second 10 both give 15, but 5,5,5,6,7 only counts as 1 "15"–all three 5s together.)

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

practice. practice. practice.

the first one, all those points on the line just make a strait line.