In δabc, ∠cad = 22° and segment cb = 15 cm. if the cos of 22° = 0.9272, then the sin of ∠c = -0.9272 0.9272 0.6537 -0.6537

Option B. 0.9272

Step-by-step explanation:

In the given triangle ABC, ∠CAD = 22° segment CB = 15 cm.

We have to find sin of ∠C.

In the given triangle ADC,

∠CAD + ∠ADC + ∠DCA = 180

22° + 90° + ∠DCA = 180

∠DCA = 180 - 112 = 68°

Now we have to get the value of sinC or sin of angle DCA

Therefore sinC = sin 68° = 0.9272

Option B. 0.9272 is the correct option.

step-by-step explanation:

abc

the answer is 11.2 (i know i’m late)