Suppose that circles a and b have a central angle measuring 40°. additionally, circle a has a radius of 5 2 ft and the radius of circle b is 9 2 ft. if the measure of the sector for circle a is 25 36 π ft2, what is the measure of the sector for circle b?

Let 

rA> radius of the circle A

rB> radius of the circle B

SA> the area of the sector for circle A

SB> the area of the sector for circle B 

we have that

rA=5/2 ft

rB=9/2 ft

rA/rB=5/9> rB/rA=9/5

SA=(25/36)π ft²

we know that

if Both circle A and circle B have a central angle , the square of the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the area of the sector for circle A to the area of the sector for circle B

(rA/rB) ^2=SA/SB> SB=SA*(rB/rA) ^2> SB=(9/5) ^2*(25/36)π--->

SB > (81/25)*(25/36) > 81/36 >  9/4π ft²

the answer is

the measure of the sector for circle B is (9/4)π ft²

it would be:

c.parallelogram.

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: