Find the value of x to the nearest tenth? -7.9 -8.1 -8.9 -7.5

First we should find the base length of the triangle (let's call this y) using Pythagoras' Theorem: c^2 = a^2 + b^2, where c is the hypotenuse and a and b are the other two sides
6^2 = 4^2 + y^2
36 = 16 + y^2
y^2 = 20
y = 4.47 (to two decimal places)

Now this y-value that we have found is actually half of x, which we can see since the length x is perpendicular to h, and thus:
4.47 = 0.5x
x = 4.47/0.5 = 8.9 (to the nearest tenth)
Thus the answer is C

Ithink the answer is b