5x+3y=-10 3x+5y=-6 using elimination?

Using the process of elimination, we will be able to determine the answer. So, 5x+3y=-10 multiply it by *3 to change the equation into 15x+9y=-30. Then to change 3x+5y=-6 multiply it by *5, to change it into 15x+25y=-30. So now with these two equations 15x+9y=-30 and 15x+25y=-30, use subtraction to get rid of the variable x.

Thus, 

15x+9y=-30
-
15x+25y=-30

which will leave you with 

-16y=0
thus, y=0

Then, plug y back into the original equation to find x

5x+3(0)=-10

5x=-10
x=-2

Thus the point of intersection is (-2,0)

-2 being the x, and y being 0.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.