Suppose an experiment consists of tossing two fair coins. if the experiment were repeated 100 times, how many times would you predict the first coin to land on heads and the second coin to land on tails?

it can vary from : 49,50,51 up to 99 number of times

Step-by-step explanation:

when two coins are tossed at the same time there are four possible outcomes

which are : H,H,  T,T  H,T  T,H

The probability of the first coin landing on Heads and the second coin landing on its tails would be: 1/2 = 0.5

Tossing the two coins several times brings the probabilities closer to the figure of : 0.5

The number of times the first coin lands on its head might not be equal to the number of times the second coin would land on its tail due to uncertainties

Although the probability is 0.5 for H,T

it can vary from : 0.49,0.50,0.51 up to 0.99

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

b

step-by-step explanation: