6,000 dollars is invested in two different accounts earning 3% and 5% interest. at the end of one year, the two accounts earned $220 in interest. how much money was invested at 5%? $2,000 $3,000 $4,000

$2000

Step-by-step explanation:

6,000 dollars is invested in two different accounts earning 3% and 5% interest.

Let x be the amount invested in account earning 3% interest

So, 6000-x is the amount invested in account earning 5% interest

So, Simple interest for account earning 3% interest

Simple interest for account earning 5% interest

Since we are given that the two accounts earned $220 in interest

So,

So, 4000 was invested at 3%

(6000-x)=6000-4000=2000 was invested at 5%

Hence 2000 was invested at 5%

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: