What is the axis of symmetry for f(x) = 2x2 − 8x + 8?

F(x)=2x^2-8x+8
This is a quadratic equation, and its graph is a vertical parabola
f(x)=ax^2+bx+c
a=2>0 (positive), then the parabola opens upward
b=-8
c=8

The Vertex is the minimum point of the parabola: V=(h,k)
The abscissa of the Vertex is:
h=-b/(2a)=-(-8)/[2(2)]=8/4→h=2

The axis of symmetry is the vertical line:
x=h→x=2

The axis of symmetry for f(x) = 2x^2 − 8x + 8 is x=2

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