Find two numbers whose difference is 120 and whose product is a minimum.

Let the numbers be x & y

Let x > y

So as the difference of the numbers is 120

We get x - y = 120

Subtracting 120 from both sides and adding y we get

y= x – 120

Now the product of the numbers be P

P= xy

P = x(x-120)

P = x² - 120x

Comparing with

We get

a= 1 & b = -120

The vertex is (h,k)

Where

h = -b/2a = -(-120)/2 = 60

So one part of the number shall be x= 60

Now y = x - 120 = 60 - 120 = -60

The numbers are -60 & 60.

2500

step-by-step explanation:

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.