Is it possible for a triangle to have sides with the given lengths: 20 m, 22 m, and 24 m? a. yes; the sum of each pair is greater than the third. b. no; 202 + 222 > 242. c. no; 22 + 24 > 20. d. yes; the sum of each pair is less than the third.

Option A. Yes; the sum of each pair is greater than the third.

Step-by-step explanation:

As we know triangle inequality theorem clearly states that a triangle is possible only when sum of two sides of the triangle is greater than third side of the triangle.

The given sides of the triangle are 20m, 22m and 24m.

so by theorem of inequality

22 + 20 > 24

42 > 24

Therefore, answer will be (A) sum of each pair is greater than third.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this