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The graph of the equation 8x–5y=14 passes through a point with an abscissa of 1.2. find the ordinate of the point.
Answers: 1
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Ahyperbola centered at the origin has a vertex at (-6,0) and a focus at (10,0)
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Given: transversal t passed through parrallel lines r and s.prove: < 3 = < 6 < 4 = < 8what is the next step in the proof? choose the most logicsl approach
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The graph of the equation 8x–5y=14 passes through a point with an abscissa of 1.2. find the ordinate...
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