Find the vertex of the parabola. y = -3x2 - 10x - 8

The x-coordinate of the vertex of a parabola y = ax^2 + bx + c is x = -b / (2a).

Here, a = -3 and b = -10, so the x-coord of the vertex is x = 10 / (2*-3), or

x = 10 / (-6)  = -5/3

and so the y-coordinate is   y = -3(-5/3)^2 - 10(-5/3) = 25/3

The vertex of this parabola is (-5/3, 25/3).            (answer)

Its d so thats how it would would back from 1.0 form three four two