What is the area of the shaded region in the given circle in terms of pi and in simplest form? a. (30 pi + 9 √3) m² b. (24 pi + 9 √3) m² c. (30 pi + 18 √3) m² d. (24 pi + 18 √3) m²

The area of the circular region is:
 A1 = ((300/360) * (pi * 6 ^ 2))
 Rewriting:
 A1 = 30pi
 Then, the trig area is:
 A2 = (1/2) * (6) * (sine (60) * 6)
 A2 = (1/2) * (6) * ((root (3) / 2) * 6)
 Rewriting:
 A2 = (3) * ((root (3)) * 3)
 A2 = (9) * (root (3))
 The area of the shaded region is the sum of the areas:
 A = A1 + A2
 Substituting values:
 A = 30pi + 9raiz (3)
 
 A. (30 pi + 9 √3) m²

W-14=t. that i think is the answer idk