Three brothers have ages that are consecutive even integers the product of the first & third boys ages is 20 more than twice the seconds boy age. find the age of each of the boys

Let's say X is the first brother's age
x+2 is second brother, and x+4 is the third brother
Since the product of the first and third boy x(x+4) is 20 more than twice (20+x(x+2), our equation is x(x+4)=20+2(x+2)
Simplify from there and see what you get.