There are 4 seats available at a table in the lunch room of an elementary school, and 12 students are looking for seats. in how many ways can the seats at the table be filled with 4 of these 12 students? 495 2,970 11,880 20,736

11880

Step-by-step explanation:

In this case, "order matters" since students A,B,C and D, can trade seats and each would be a different way of seating the students (even though it is the same 4 people).

Therefore, use the permutations formula to calculate the answer

12P4= n!/(n-r)!

= 12!/(12-4)!  

=12!/8!

=11880 ways

(Plus I took the test on Edge and got it right)

answer:

c 60% on edg

find the magnitude of the trig term  

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x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

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[

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,

∞

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{

y

|

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,

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step-by-step explanation: