Abag contains 5 blue marbles and 8 orange marbles. polly draws a marble from the bag and keeps the marble. perry then draws a marble from the bag. what is the probability that both polly and perry draw an blue marble from the bag? 5/39 39/5 9/25 1

There are a total of 13 marbles in the bag. (5 blue marbles and 8 orange marbles)

We know that Polly draws first. She draws the marble from the bag and keeps the marble. Now, let "A" be the event that Polly draws a blue marble from the bag. Then the probability of the event A occurring will be given by:

Now, given that Polly has already drawn a blue marble from the bag we know that the total number of marbles in the bag will now get reduced by 1 and thus will become 12. Likewise, the total number of blue marbles will become 4.

Let "B" be the event that Perry draws a blue marble from the bag. The probability of the event B occurring is:

Thus, the the probability that both Polly and Perry draw an blue marble from the bag will be given by:

P(A and B)=

Out of the given options, the first option in the correct one. The answer is .

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3