Use the four step process to find the slope of the tangent line to the graph of the given function at any point. f(x)= -10x^2+7x

1) x=x+h→F(x+h)=-10(x+h)^2+7(x+h)
Using (a+b)^2=a^2+2ab+b^2, with a=x and b=h
F(x+h)=-10[(x)^2+2(x)(h)+(h)^2]+7x+7h
F(x+h)=-10(x^2+2xh+h^2)+7x+7h
F(x+h)=-10x^2-20xh-10h^2+7x+7h

2) F(x+h)-F(x)=(-10x^2-20xh-10h^2+7x+7h)-(-10x^2+7x)
F(x+h)-F(x)=-10x^2-20xh-10h^2+7x+7h+10x^2-7x
F(x+h)-F(x)=-20xh-10h^2+7h

3) [F(x+h)-F(x)]/h=(-20xh-10h^2+7h)/h
[F(x+h)-F(x)]/h=-20xh/h-10h^2/h+7h/h
[F(x+h)-F(x)]/h=-20x-10h+7

4) Lim h→0 [F(x+h)-F(x)]/h=Lim h→0 (-20x-10h+7)
Lim h→0 [F(x+h)-F(x)]/h=-20x-10(0)+7
Lim h→0 [F(x+h)-F(x)]/h=-20x-0+7
Lim h→0 [F(x+h)-F(x)]/h=-20x+7

The slope of the tangent line to the graph of the given funtion at any point is m=-20x+7

Iwould say this is false, because the mean and median are similar, though the mode is way different. but it might be true depending how you like at it. sorry if i'm being confusing : )