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17x² - 8x - 4 = 0

Explanation:
First, we would need to expand the bracket on the right:
(4x-1)² = (4x)² - 2(4x)(1) + (1)²
(4x-1)² = 16x² - 8x + 1

The given equation now becomes:
-x² + 5 = 16x² - 8x + 1

Now, the standard form of the quadratic equation is:
ax² + bx + c = 0

This means that we want all the terms on one side and a zero on the otehr.
Therefore:
-x² + 5 = 16x² - 8x + 1
-x² + 5 - 16x² + 8x - 1 = 0
-17x² + 8x + 4 = 0
Multiply all terms by -1 to get a positive value for the coefficient of the x².
This will give:
17x² - 8x - 4 = 0

Hope this helps :)

The answer is the numbers between =5 and 5