Anita invested $6000, some at 5% and the rest at 6%. if the yearly income is $337.50, what is the amount invested at each rate? '

Anita invested $3750 at 6%.

Anita invested $2250 at 5%.

Step-by-step explanation:

Let x be amount of money invested at 5% and y be the amount of money invested at 6%.

We have been given that Anita invested $6000, some at 5% and the rest at 6%. We can represent this information in an equation as:

The income from the money invested at 5% will be equal to 5% of x (0.05x). The income from the money invested at 6% will be equal to 6% of y (0.06y).

We are also told that the yearly income is $337.50. We can represent this information in an equation as:

We will use substitution method to solve our system of equations.

From equation (1) we will get,

Substituting this value in equation (2) we will get,

Therefore, Anita invested $3750 at 6%.

Upon substituting in equation (1) we will get,

Therefore, Anita invested $2250 at 5%.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

idk u tell me

step-by-step explanation: