Find the lateral area of the right prism with height 0.3 dm, if the base of the prism is: b parallelogram with sides of 6 cm and 20 mm

We consider the following conversion of units:
 10 dm = 1 m
 100 cm = 1 m
 1000 mm = 1m
 For this case the lateral area is given by:
 rectangle 1:
 A1 = (0.3 * (1/10)) * (6 * (1/100))
 A1 = 0.0018 m ^ 2
 Rectangle 2:
 A2 = (0.3 * (1/10)) * (20 * (1/1000))
 A2 = 0.0006 m ^ 2
 The lateral area is:
 A = 2 * A1 + 2 * A2
 A = 2 * (0.0018) + 2 * (0.0006)
 A = 0.0048 m ^ 2
 
 The lateral area of the right is:
 A = 0.0048 m ^ 2

The answer of the above question is

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!