Mathematics, 22.07.2019 08:00 Kimmie2019

Find the area of a square that is 1/2 yd on a side.

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Answer from: u8p4

  " $\frac{1}{4}$ yd²  " .

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The area of the square is:  " $\frac{1}{4}$ yd²  " .

or; write as: " 0.25 yd² " .
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Explanation:
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A "square", by definition, is a quadrilateral and a rectangle, with 4 (four) equal sides and 4 (four) equal angles.

The formula for the area of a square is:

" A = s² " ;

in which: " A = area of the square" ;

(in " square units "; in our case, " square yards " ;
or, write as: " yd² " .
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" s = side length = " 1/2 yd " ; {given} .
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To find the "Area, "A" ; of the square, which is what the question asks:

→ We plug in the given / known values into the formula, & solve:

→ " A = s² " ;

→ A = (1/2 yd)² ;

=  (1/2)² * yd² ;

  = (1/2) * (1/2) * yd² ;

   = (1 * 1) / (2 * 2) * yd² ;

  = " 1/4 yd² " .
______________________________________________________
" $\frac{1}{4}$ yd² " .

______________________________________________________
The area of the square is: " $\frac{1}{4}$ yd² " .

or; write as: " 0.25 yd² " .
______________________________________________________

Answer from: Quest

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

Answer from: Quest

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c

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