Using the discriminant, what values of c will make the quadratic y = 2x2 - 3x + c have one real solution?

The discriminant is b^2-4ac in the equation ac^2+bx+c
so taking 2x^2-3x+c we have discrimant of
(-3)^2-4(2)c which simplifies to 9-8c
one real solution happens when the discrimnant is 0 so we have
9-8c=0 so 9=8c and c=9/8
so when c is 9/8 we will have 1 real solution
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