Question 2(multiple choice worth 2 points) (09.06) the steps for circumscribing a circle about a triangle are shown: step 1 construct the perpendicular bisector of one side of the triangle. step 2 construct the angle bisector of another side of the triangle. step 3 indicate the point of intersection of the perpendicular bisectors with a point representing the center of the circle. step 4 place the compass on the center, adjust its length to reach any vertex of the triangle, and draw your circumscribed circle. what is the first incorrect step, and how can it be fixed? step 2, replace angle bisector with perpendicular bisector step 3, circle should be triangle step 4, replace center with vertex of the triangle all steps are correct.

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step-by-step explanation:

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step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: