Use the distance formula d= √ (x2-x1)^2+(y2-y1)^2 to find the length of the line with endpoints at (1,3) and (3,1)? √8 8 √32 32

We have that
line with endpoints at (1,3) and (3,1)

we know that

Applying the distance formula
d= √ (x2-x1)^2+(y2-y1)^2
d= √ (3-1)^2+(1-3)^2> d=√[2²+(-2)²]> d=√8

10feet apart then both

10,000 hope i ! : )