Given that a=43 degrees , b=82 degrees and c=28, solve triangle abc. round to the nearest hundredth. a) c= 93 degrees , b= 33.8 , a= 23.3 b) c= 55 degrees , b= 33.8 , a= 23.3 c) c= 55 degrees , b= 23.3 , a= 33.8 d) c= 93 degrees , b= 23.3 , a= 33.8

The angles of the triangle can be determined by cosine law

a^2 = b^2 + c^2 - 2bccosA

substituting;
(43^2)=(82^2)+(28^2)-2(82)(28)cosA

A=23.3 degrees

and the other angles can be determined using sine law

sin A/ a = sin B/ b = sin C/ c

Thus, 
B= 33.8 degrees
and 
C= 55 degrees

Iam guessing c. or d.