Ireally need . part a: explain why the x-coordinates of the points where the graphs of the equations y = 4^−x and y = 8^(−x−1) intersect are the solutions of the equation 4^−x = 8^(−x−1). (4 points) part b: make tables to find the solution to 4^−x = 8^(−x−1). take the integer values of x between −3 and 3. (4 points) part c: how can you solve the equation 4^−x = 8^(−x−1) graphically? (2 points)

I'm pretty sure the answer to A would be this: the common point that satisfies both equations (where they intersect) can be shown AS 4^(-x) = 8^(-x-1). 

The answer to B is forming a table. This is quite easier than you think :D.

Start with x on one side (3) and go all the way down to -3 like this:

(x)    4^-x    8^-x-1
-3      64       (Do the same with this)
-2      16
-1       4
0        1
1       1/4
2     .0625 
3   .015625  

So basically you just fill in the x variable with every number between 3 and -3. After that, it's just a bit of math and you've done it!

C is a bit misguided. I think it would be quite simple to just use a graphing calculator, but you would have to actually input all the x and y values from the table. After that, you will have a graph.

I hope I helped! Good luck and good day!

The coordinates of point a right now is (-3,-1) you have to multiply these coordinates by a factor of 2 to get (-6,-2)

Aline graph should be used