Suppose that circles r and s have a central angle measuring 80°. additionally, circle r has a radius of 3 ft and the radius of circle s is 6 ft. if the measure of the sector for circle r is 2π ft2, what is the area of the sector for circle s?

Let 

rA> radius of the circle R

rB> radius of the circle S

SA> the area of the sector for circle R

SB> the area of the sector for circle S

we have that

rA=3 ft

rB=6 ft

rA/rB=3/6> 1/2> rB/rA=2

SA=2π ft²

we know that

if Both circle A and circle B have a central angle , the square of the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the area of the sector for circle A to the area of the sector for circle B

(rA/rB) ^2=SA/SB> SB=SA*(rB/rA) ^2> SB=(2) ^2*(2π)--->

SB > 8π ft²

the answer is

its definatley   this on your answer choice?

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.