Look at the figure below: triangles abc and acd have a common side ac. e is the point of intersection of ad and bc. ae equals ed and ce equals be. based on the figure, which pair of triangles is congruent by the side angle side postulate? triangle acd and triangle ace triangle aec and triangle dec triangle abe and triangle ace triangle aeb and triangle dec

Side Angle Side Postulate. The Side Angle Side postulate (often abbreviated as SAS) states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.

We are given the following:

side AE = ED

side CE = BE

Since, side AD and BC can be extended to meet at point E (point of intersection), so ∠AEB = ∠DEC

So by SAS property ΔAEB ≅ ΔDEC

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!