Iam first going to try finding the tangent line at this point: take the derivative: dy/dx = (3x^2 - e^x)/2y solve using (0, 1) dy/dx = (0 - 1)/6 = -1/6 i believe that -1/6 is the slope of the tangent line, so the slope of the normal line should be +6, right?

Which point on the scatter plot is an outlier? a scatter plot is show. point m is located at 3 and 3, point p is located at 5 and 5, point n is located at 5 and 7, point l is located at 6 and 2. additional points are located at 1 and 3, 2 and 3, 2 and 4, 3 and 4, 3 and 5, 4 and 5, 4 and 6, 5 and 6. point p point n point m point l