Use the graph below to answer the question that follows: what are the amplitude, period, and midline of the function? amplitude: 4; period: 2π; midline: y = −1 amplitude: 8; period: 2π; midline: y = 1 amplitude: 8; period: π; midline: y = −1 amplitude: 4; period: π; midline: y = 1

Amplitude : 4

Period: 2π

Mid-line: y=-1

A is correct

Step-by-step explanation:

We are given graph of periodic function.

We need to find amplitude, period and midline of the function.

From graph:

Maximum value  = 3

Minimum value = -5

The mid-line equation, y=-1

Amplitude: Distance between mid-line and maximum value

Amplitude = 3-(-1) = 4

The amplitude of given graph is 4

Period: It is time when graph repeat their path.

In the given graph repeat their in 2π of interval.

The period of graph is 2π

step-by-step explanation:

i found the koficent of the linear function and i foun c acordind to the strict formula y=kx+c and then i took 2 as an x and replacet it on the formula i found and then foun the y

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1