Will mark as brainliest. michaela drops a ball vertically from a height of 80 feet. the peak height after each bounce is half the previous height. how far does the ball travel from the time she drops it until it reaches the peak height after the 5th bounce? 155 ft 230 ft 232.5 ft 312.5 ft

Answer with Step-by-step explanation:

We are given that:

Michaela drops a ball vertically from a height of 80 feet. The peak height after each bounce is half the previous height.

We have to find how far the ball travel from the time she drops it until it reaches the peak height after the 5th bounce.

At first it travel 80 feet

first bounce occurs then comes up 40 feet and goes down 40 feet.

second bounce occurs after that it comes up 20 feet and goes down 20 feet.

third bounce occurs after that it comes up 10 feet and goes down 10 feet.

fourth bounce occurs after that it comes up 5 feet and goes down 5 feet.

now at fifth bounce it comes up to 2.5 feet

total distance traveled from starting to the time it reaches the peak height after 5th bounce is:

80+40+40+20+20+10+10+5+5+2.5

= 232.5 feet

Hence, third option is correct i.e. 232.5 ft