Student made five tetrahedrons, a three dimensional figure with four triangular faces and labeled the faces 1-4. use an equation to find the probability that all five tetrahedrons land on 3. how do i do this? i don't understand

The probability is 1/1024.

Each tetrahedron has a 1/4 chance of landing on 3, since there are 4 sides and only one of them is marked 3.

Each tetrahedron roll is independent, since no roll is affected by another.

This means we multiply the probabilities:

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your answer is a

step-by-step explanation:

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7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐