What percent of a drug is contained in a mixture of powder consisting of 0.5 kg, containing 0.038% of a drug, and 10 kg, containing 0.043% of a drug?

0.043% is the percentage of the drug contained in the mixture.

Explanation:

We know that 0.5kg contains 0.038% of a drug, so the 100% is 0.5 kg, but 0.038% how many kilograms are?

100%0.5kg

0.038%x= 0.00019kg

0.5kg contains 0.00019kg of drug

We also know that 10kg contain 0.043% of a drug, so if the 100% is 10kg 0.043 how many kilograms are?

100%10kg

0.043%X= 0.0043kg

10kg contains 0.00043kg of drug.

Now we have to calculate the total mass of drug and the total mass of the mixture

0.00019kg +0.0043kg= 0.00449kg of drug.

0.5kg+10kg= 10.5kg of mixture.

Finally, we have to calculate the percentage of drug in this mixture

10.5kg100%

0.00449kgX=0.043%

The percentage of drug in the mixture is 0.043%

answer:

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answer:

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