Acable capable of pulling 4,500 n snapped while trying to drag a 20,000 n compressor across the street. what is the coefficient of static friction for this scenario? note: the 4500 n cable is used as fs and is calculated the same as fk 0.225 > 0.225 4,500 n > 4,500 n 4.44 > 4.44 explain to me how you get your answer.

Explanation:

The cable snapped because the frictional force was greater than the tension in the rope:

Now,

where is the coefficient of static friction, and is the normal force. In our case, the normal force on the compressor is 20,000 N; therefore,

.

Putting this into the condition , we get:

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a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation: