At an ocean depth of 10.0 m, a diver’s lung capacity is 2.40 l. the air temperature is 32.0°c and the pressure is 101.30 kpa. what is the volume of the diver’s lungs at the same depth, at a temperature of 21.0°c and a pressure of 141.20 kpa?

V = 1.66 L

Explanation:

As we know that at the depth of 10 m the volume of the lungs of diver is given as

V = 2.40 L

Temperature = 32 degree C

Pressure = 101.30 kPa

Now we have change the values of pressure and temperature

Pressure = 141.20 kPa

Temperature = 21 degree C

Now we can use idea gas equation to solve this

so we have

radiation warms things up temp rises convection currents air circ windy weather

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it