The plates on a vacuum capacitor have a radius of 3.0 mm and are separated by a distance of 1.5 mm. what is the capacitance of this capacitor? recall that ε0 = 8.85 × 10–12

Capacitance is the ratio of the change in an electric charge in a system to the corresponding change in its electric potential. For a Parallel-plate capacitor, the formula to calculate the capacitance is given by:



being:

: the electric constant 
: the area of overlap of the two plates, in square meters
:  he separation between the plates, in meters

Given that the plates of the capacitor have Circular Cross-Section, then:



Therefore, the capacitance is:

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