Physics, 19.07.2019 20:00 jagdeep5533

Why are smaller planets less geologically active than larger planets?

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Answer from: hdkdkdbx

Each planet has a 'planetary body' that are pretty much always hot when they are being created. As time passes, that internal heat that causes geological activity is slowly lost. Larger planet bodies are able to keep the internal heat longer than smaller planets, and that heat is needed to keep the planets geologically active.
The only way a smaller planet can retain any heat is from tidal friction coming from another planet. The constant friction from the external body keeps that small planet from going completely cold to the core due to its size. Hope this helps!! :)

Answer from: neariah24

The larger planets have more heat internally where as the smaller planets dont to keep thme geologically alive so to speak

Answer from: Quest

Ithink it is c ,i hope i you

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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