Can i get answers 14 through 18 ? plz show work number !

14). c
15). c
16). a little less than d
17). a

18).
-- The parallel combination of 4Ω, 6Ω, and 10Ω is 1.935Ω .

-- The battery sees 1.935Ω in series with 2Ω. That's 3.935Ω .

-- The voltage across the 3 parallel resistors is (1.935/3.935)
of the total battery voltage. That's about 5.9 volts.

-- I = V/R .
The current in the 10Ω resistor is (5.9v/10Ω) = 0.59 Amp. (choice-a)

Does this your question?

Idont understand the question