Apoint charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram. what is the magnitude of the magnetic force acting on the charge? 6.6 × 10–3 n 4.9 × 10–3 n 4.9 × 103 n 6.6 × 103 n

Explanation:

The magnitude of the magnetic force acting on the charge is given by

where

is the magnitude of the charge

is the velocity of the charge

is the magnitude of the magnetic field

is the angle between the directions of v and B

Substituting the numbers into the equation, we find:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

radiation

explanation:

heat is transmitted by radiation