Asky diver jumps out of an airplane at a height of 5010 ft. if her parachute does not open until she reaches 1010 ft, what is her velocity (in ft/s) at that point if air resistance is neglected?

Given:

Height from which diver jumps h(i)=5010 ft

Height from which diver open the parachute h(f)=5010 ft

calculate the net height h= h(i)-h(f)

substitute the values in the above equation

h= 5010-1010= 4000 ft

calculate the velocity of the diver at the net height.

here g is acceleration due to gravity = 32.2 ft per second square

h is the net height

substitute the values in the above equation

the chart show the masses and velocities of two colliding objects that stick together after a collision.

according to the law of conservation of momentum, the momentum of the object after the collision is  

answer

1,500

kg • m/s.