Astone was dropped off a cliff and hit the ground with a speed of 104 ft/s. what is the height of the cliff? (use 32 ft/s2 for the acceleration due to gravity.)

Let the stone is dropped off a cliff of height S m ft.

Given, initial velocity of the stone, u= 0 ft/s

Final velocity of the stone, v= 104 ft/s

Acceleration of the stone= Acceleration due to gravity = 32 ft/s²

Using the third equation of motion,

v² - u² = 2aS

Substituting the values we get,

S= 169 ft

Height of the cliff is 169 ft.

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle