Physics, 14.07.2019 01:00 enchantednights
Arectangular loop of wire (8.0 cm by 3.0 cm) is in the x-y plane. there is a magnetic field of 4.5 t in the y-z plane that makes an angle of 30o with the y-axis. what is the flux through the loop.
Answers: 1
![B = 4.5 (cos30 (j) + sin30 (k))[\tex][tex]B = 3.89 j + 2.25 k](/tpl/images/0086/7978/7a957.png)
![\phi = B. A[\tex][tex]\phi = (3.89 j + 2.25 k ).(24 * 10^{-4} k)](/tpl/images/0086/7978/2b52b.png)
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Arectangular loop of wire (8.0 cm by 3.0 cm) is in the x-y plane. there is a magnetic field of 4.5 t...
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