An iron block of mass 18 kg is heated from 285 k to 318 k. if 267.3 kj is required, what is the specific heat of iron

q = mcΔT

where, q = heat required in Joules

m = mass in grams

c = specific heat in joules/gram °C

ΔT = change in temperature = Final temperature(T₂)-Initial Temperature (T₁)

Given, q=267.3 kJ=267300 Joules

m=18kg=18000 gram

ΔT=318-285= 33K = 33°C

Rearranging formula, c=

c=

c=0.45 joules/gram °C

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

what is the actual question though?