Three deer, a, b, and c, are grazing in a field. deer b is located 62m from deer a at an angle of 51° north of west. deer c is located 77° north of east relative to deer a. the distance between deer b and c is 95m. what is the distance between deer a and c?

Based on the data given, the distance between deer A and C is 119.6 m

Using the information provided, a triangle ABC is formed

Using sine rule to find the angle at B

C = sin¹ (c * Sin A/a)

C = sin¹ (62 * sin 52/95)

C = 31°

Therefore;

angle at B = 180 - (52 + 31)

angle at B = 97°

Using cosine rule to find side AC

b² = 95² + 62² - 2 * 95 * 62 * cos97

b = 119.6 m

Therefore, the distance between deer A and C is 119.6 m

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Set deer A's position to be the origin. Let be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector is 95 (or ). Then

layers of the earth affect the waves and these effects are seen on instruiments such as seimometers