If a 3-kg rabbit's leg muscles act as imperfectly elastic springs, how much energy will they hold if the rabbit lands from a height of 0.5 m and its legs are compressed by 0.2 m?

U = 14.7 J

Explanation:

Loss in gravitational potential energy is stored in the form of potential energy of rabbit legs

So here we will have by energy conservation

gravitational potential energy = energy stored in the legs

so here we will have

gravitational potential energy given as

m = 3 kg

g = 9.81 m/s/s

h = 0.5 m

now we have

as technology advances, new experiments often expose problems in accepted theories. c

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-lavira: )

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